2v^2+15v+17=0

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Solution for 2v^2+15v+17=0 equation: 



2v^2+15v+17=0

a = 2; b = 15; c = +17;
Δ = b2-4ac
Δ = 152-4·2·17
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{89}}{2*2}=\frac{-15-\sqrt{89}}{4}
$


$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{89}}{2*2}=\frac{-15+\sqrt{89}}{4}
$

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